Resposta :
[tex]4x^4-9x^2+2=0 \\
Fazendo \ y=x^2 \\
4y^2-9y+2=0 \\
\Delta=(-9)^2-4.4.2=81-32=49 \\
y=\frac{9+-7}{8} \\
y_1=\frac{1}{4}= \\
y_2=\frac{16}{8}=2 \\
Logo: \\
x_1, x_2=+-\sqrt{\frac{1}{4}}=+-\frac{1}{2} \\
\\
x_3,x_4=+-\sqrt2[/tex]