Resposta :
(3m+2)x²+(2n-1) x-t = 0
3m + 2 = 0 ==> 3m = - 2 ==> m = - 2/3
2n - 1 = 0 ==>2n = 1 ==> n = 1/2
- t = 0 ==> t = 0
3m + 2 = 0 ==> 3m = - 2 ==> m = - 2/3
2n - 1 = 0 ==>2n = 1 ==> n = 1/2
- t = 0 ==> t = 0