Oi Amanda,
[tex]\frac{\log4+\log9+\log25}{1+\log k}=2\\\\\log4+\log9+\log25=2(\log10+\log k)\\\\\log(4\cdot9\cdot25)=2\cdot\log10+2\cdot\log k\\\\\log(4\cdot9\cdot25)=\log10^2+\log k^2\\\\\log(4\cdot9\cdot25)=\log100+\log k^2\\\\\log(4\cdot9\cdot25)=\log(100\cdot k^2)[/tex]
[tex]4\cdot9\cdot25=100\cdot k^2\\\\100k^2=900\\\\k^2=9\\\\k=\sqrt{9}\\\\\boxed{k=3}[/tex]