Resposta :
d=L [tex] \sqrt{2} [/tex]
10[tex] \sqrt{2} [/tex] = L [tex] \sqrt{2} [/tex]
L=10[tex] \sqrt{2} [/tex] / [tex] \sqrt{2} [/tex]
L=[tex]10 \sqrt{2} / \sqrt{2} [/tex] . [tex] \sqrt{2} / \sqrt{2} [/tex]
L=10 . 4 / 2
L=40/2
L=20
p= soma dos lados
p= 20+20+20+20
p=80 cm
10[tex] \sqrt{2} [/tex] = L [tex] \sqrt{2} [/tex]
L=10[tex] \sqrt{2} [/tex] / [tex] \sqrt{2} [/tex]
L=[tex]10 \sqrt{2} / \sqrt{2} [/tex] . [tex] \sqrt{2} / \sqrt{2} [/tex]
L=10 . 4 / 2
L=40/2
L=20
p= soma dos lados
p= 20+20+20+20
p=80 cm