Resposta :

Celio

Olá, Renata.

 

[tex][cateto]^2+[cateto]^2=[hipotenusa]^2[/tex]

 

[tex] \Rightarrow (\sqrt{10})^2+(\sqrt{10})^2=[hipotenusa]^2[/tex]

 

[tex]\Rightarrow [hipotenusa]^2=10+10[/tex]

 

[tex] \Rightarrow [hipotenusa]^2=20 \Rightarrow [hipotenusa]=\sqrt{20}=\sqrt{2^2 \cdot 5}[/tex]

 

[tex] \Rightarrow [hipotenusa] = 2\sqrt5[/tex]

justinianolima

[tex]h^2=(\sqrt{10})^2+(\sqrt{10})^2 \\h^2=10+10=20 \\h=\sqrt{20}=\sqrt{2^2*5}\\h=2\sqrt5[/tex]

 

ou

[tex]h=cat\sqrt{2}\\h=\sqrt{10}*\sqrt{2}\\h=\sqrt{20}\\h=\sqrt{2^2*5}\\ h=2\sqrt{5}[/tex]

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