Resposta :
[tex]\boxed{a) d=\sqrt{(1-5)^2+(-2+2)^2}=\sqrt{(-4)^2+0^2}=\sqrt{4}=2}[/tex]
[tex]\boxed{b) d=\sqrt{(5-2)^2+(3-1)^2}=\sqrt{3^2+2^2}=\sqrt{9+3}=\sqrt{13}}[/tex]
[tex]\boxed{b) d=\sqrt{(5-2)^2+(3-1)^2}=\sqrt{3^2+2^2}=\sqrt{9+3}=\sqrt{13}}[/tex]