Resposta :
a) M AB de (1,7) e (11,3) ===>
(1 + 11)/2 = 6 ==> (7 + 3 )/2 = 10/2 = 5 ==> o ponto médio de AB = (6,5)
b) M AB de (11,3) e (-4,-1) ==>
[11+(-4)]/2, [3+(-1)] : 2 = (7/2, 2/2) = (7/2, 1)
c) M AB de (
(1 + 11)/2 = 6 ==> (7 + 3 )/2 = 10/2 = 5 ==> o ponto médio de AB = (6,5)
b) M AB de (11,3) e (-4,-1) ==>
[11+(-4)]/2, [3+(-1)] : 2 = (7/2, 2/2) = (7/2, 1)
c) M AB de (