Resposta :

Bowlt
[tex] x^{2} = 4^{2} + 3^{2} \\\\x^{2} = 16 +9\\\\ x^{2} = 25\\\\x= \sqrt{25} \\\\ x= 5[/tex]
wandersonoliveira
[tex] x^{2} = 4^{2}+ 3^{2} [/tex]
[tex] x^{2} =16+9[/tex]
[tex] x^{2} =25[/tex]
x=[tex] \sqrt{25} [/tex]
x=[tex]5[/tex]
do ponto A ate o C  tem 5 m

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