Resposta :

[tex][tex]2x+ x^{2} =8 [/tex][tex] x^{2} +2x-8=0[/tex]/[tex]delta= 2^{2}-4.1.-8 /delta=4+32/delta=36 [/tex][/tex]
[tex]x= \frac{-(4)mais/menos \sqrt{36} }{2.1} [/tex]
[tex]x= \frac{-4mais/menos6}{2} [/tex]
[tex] x^{1} = \frac{4+6}{2} [/tex][tex] [tex] x^{1}=5 [/tex][/tex]
[tex] x^{2} = \frac{4-6}{2} [/tex] [tex] x^{2} =-1[/tex]
[tex]2x+x^2=8\Longrightarrow x^2+2x-8=0\\\\ \Delta=b^2-4\cdot a\cdot c\\ \Delta=2^2-4\cdot1\cdot(-8)\\ \Delta=4+32\\ \Delta=36\\\\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-2\pm\sqrt{36}}{2\cdot1}=\dfrac{-2\pm6}{2}=-1\pm3\Longrightarrow\begin{cases}x_1=2\\x_2=-4\end{cases}\\\\ S=\{-4,2\}[/tex]

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