Resposta :
[tex]11(x+2)-410=2(2x-4)+89\\\\
11x+22-410=4x-8+89\\\\
11x-388=4x+81\\\\
7x=469\\\\
x=\dfrac{469}{7}\\\\
\boxed{x=67}[/tex]
11(x+2)-410=2(2x-4)+89
11x +22 -410 = 4x -8 +89
11x - 4x = 89 +410 -8 -22
7x = 499-30
7x= 469
x= 469/7
x= 67
11x +22 -410 = 4x -8 +89
11x - 4x = 89 +410 -8 -22
7x = 499-30
7x= 469
x= 469/7
x= 67