Resposta :
(2x+i).(1-xi)
2x - 2x^2i + i - x.i^2
2x + x - 2x^2i + 1i
3x + (- 2x^2 + 1)i
-2x^2 + 1 = 0
-2x^2 = - 1(-1)
2x^2 =1
x^2 = 1/2
x = +/- V1/2
x = +/- V2
2
2x - 2x^2i + i - x.i^2
2x + x - 2x^2i + 1i
3x + (- 2x^2 + 1)i
-2x^2 + 1 = 0
-2x^2 = - 1(-1)
2x^2 =1
x^2 = 1/2
x = +/- V1/2
x = +/- V2
2