Resposta :

PeH
[tex]x^2 - x - 24 = 0 \\\\ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\ x = \frac{1 \pm \sqrt{(-1)^2 - 4 \cdot 1 \cdot (-24)}}{2 \cdot 1} \\\\ x = \frac{1 \pm \sqrt{1 + 96}}{2} \\\\ x = \frac{1 \pm \sqrt{97}}{2} \rightarrow x_1 = \frac{1 + \sqrt{97}}{2} \ e \ x_2 = \frac{1 - \sqrt{97}}{2} \\\\ \boxed{\text{S} = (\frac{1 - \sqrt{97}}{2}, \frac{1 + \sqrt{97}}{2})}[/tex]
AntoniLAD
[tex] x^{2} -x-24=0=
\Delta= b^{2} -4.a.c=
\Delta= 1^{2} -4.1.(-24)=
\Delta=1+96=97
x^{1} =-1-+ \sqrt{97} /2=1+ \sqrt{97}
x^{2} =-1-+ \sqrt{97} /2=1- \sqrt{97} [/tex]

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