Resposta :
[tex]F= \frac{kQq}{d^2} [/tex]
[tex]F'= \frac{kQq}{(d/2)^2} = \frac{kQq}{d^2/4} = kQq \frac{4}{d^2} =4 \frac{kQq}{d^2} [/tex]
Portanto F'=4F
Alternativa D.
[tex]F'= \frac{kQq}{(d/2)^2} = \frac{kQq}{d^2/4} = kQq \frac{4}{d^2} =4 \frac{kQq}{d^2} [/tex]
Portanto F'=4F
Alternativa D.