Resposta :
x³ - 4x² + 3x = 0
x(x² - 4x+3) = 0
x'=0
x''= x² -4x+3
a=1; b=-4; c=3
Delta=b²-4ac
Delta= (-4)²-4.1.3
Delta= 16 - 12
Delta= 4
x= -b+/- VDelta / 2.a
x= +4 +/- V4 /2.1
x= 4+/- 2 /2
x'= 4+2 / 2 => 6/2 => 3
x²= 4-2 /2 => 2/2 => 1
S= {1,3}
x(x² - 4x+3) = 0
x'=0
x''= x² -4x+3
a=1; b=-4; c=3
Delta=b²-4ac
Delta= (-4)²-4.1.3
Delta= 16 - 12
Delta= 4
x= -b+/- VDelta / 2.a
x= +4 +/- V4 /2.1
x= 4+/- 2 /2
x'= 4+2 / 2 => 6/2 => 3
x²= 4-2 /2 => 2/2 => 1
S= {1,3}