klai
Respondido

Me ajudem =)

 

sejam z1= -1+6i e z2= 3-2i calcule:

 

a) z1+z2

b)z1-z2

c)z1.z2

d)z1²                                                                                                                                                                 

Resposta :

z1= -1+6i e z2= 3-2i            i²=-1


a)
z1+z2=-1+6i + 3-2i = 2+4i
b)
z1-z2=-1+6i -( +3-2i)=-1+6i-3+2i=-4+8i
c)
z1.z2=(-1+6i).( +3-2i)=-3+2i+18i-12.i²=-3+20i+12=9+20i
d)
z1²  =(-1+6i).(-1+6i)=1-6i-6i+36i²=1-12i-36=-35-12i







3478elc


a) z1+z2  = -1+6i + 3-2i==> 2 + 4i

b)z1-z2 = -1+6i -( 3-2i) ==> - 1 +6i - 3 + 2i ==> - 4 + 8i

c)z1.z2= ( -1+6i)( 3-2i)==> - 3 +2i +18i - 12i^2==> -3+12 + 20i ==> 9 + 20i

d)z1² = ( -1+6i )^2 ==> 1 - 12i + 36i^2 ==> 1 - 12i - 36 ==> - 35 - 12i                                                                                                                                                               

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