Resposta :

[tex]\sqrt{12^{2}+8^{2}+2(12\cdot8)\cdot}cos120=

\sqrt{144+64+2\cdot96\cdot cos120=

\sqrt{208+192\cdot cos 120}=

\sqrt{208+192\cdot -1/2}=

\sqrt{208-(192\cdot 1/2)]=

\sqrt{208-96}=

\sqrt{112}[/tex]

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