Resposta :
[tex]3^{x-1}+3^{x+1}=\frac{13}{27} \\
\\
\frac{3^x}{3}}+3^x.3=\frac{13}{27} \\
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9.3^x+81.3^x=13 \\
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fazendo \ y=3^x \\
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9y+81y=13 \\
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90y=13 \\
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y=\frac{13}{90} \\
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3^x=\frac{13}{90} \\
[/tex]
[tex]3^x=\frac{13}{90} \\ log3^x=log13-log90 \\ xlog3=log13-log90 \\ \\ x=\frac{log13-log90}{log3} \\ \\ \boxed{x=-1,7611}[/tex]
-2 < x < -1
[tex]3^x=\frac{13}{90} \\ log3^x=log13-log90 \\ xlog3=log13-log90 \\ \\ x=\frac{log13-log90}{log3} \\ \\ \boxed{x=-1,7611}[/tex]
-2 < x < -1