Resposta :

MATHSPHIS
[tex]A=\frac{2a(x+1)}{a^2-1}+\frac{a-x}{a+1} \\ \\ A=\frac{2ax+2a}{a^2-1+}+\frac{a-x}{a+1} \\ \\ A=\frac{2ax+2a+(a-1)(a-x)}{a^2-1} \\ \\ A=\frac{2ax+2a+a^2-ax-a+x}{a^2-1} \\ \\ A=\frac{a^2+(a+1)x+a}{a^2-1} \\ \\ A=\frac{(a+1)(a+x)}{a^2-1} \\ \\ \boxed{A=\frac{a+x}{a-1}}[/tex]

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