Resposta :

3478elc

a) (4+i)+(3+3i)
  4 + 3 + i + 3i = 7  + 4i

b) ( 11- i^2) - (5+2i^2)
     11 - (-1) -( 25 + 20i + 4i^2)
     11 + 1 - 25 - 20i + 4.1
             - 9 - 20i 

c) (5+2i)2 * (1+i)

    (25 + 20i + 4i^2)x(1+i)
    (25 + 20i - 4)x(1+i)
    ( 21 + 20i )(1+i)
     21 +21i +20i + 20i^2
     21 - 20 + 41i
          1 + 41i

 
korvo
NÚMEROS COMPLEXOS
Operações com números Complexos

[tex]a)(4+i)+(3+3i)=7+4i[/tex]


[tex]b)(11-i ^{2})-(5+2i ^{2})=11- i^{2}-5-2i ^{2}=6-3i ^{2} [/tex]


[tex]c)(5+2i) ^{2}(1+i)=(5+2i)(5+2i)(1+i)=25+10i+10i+4i ^{2}(1+i) [/tex]

[tex]25+20i+4i ^{2}(1+i)=25+20i+4(-1)(1+i) [/tex]

[tex]25-4+20i(1+i)=(21+20i)(1+i)=21+21i+20i+20i ^{2} [/tex]

[tex]21+41i+20(-1)=21+41i-20=1+41i[/tex]

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