Resposta :
[tex]a)( \sqrt{ 0,1})^{x}= \sqrt[3]{10} = (\sqrt{ \frac{1}{10} } )^{x}=( \sqrt{10^{-1}} )^{x}=(10^{ \frac{-1}{2} })^{x}=10^-{ \frac{x}{2} }=10^ \frac{1}{3} =>- \frac{x}{2} = \frac{1}{3} =>x=- \frac{2}{3} [/tex]
[tex]b) (\frac{3}{5} )^{-x+2}= \sqrt[3]{ \frac{5}{3} } = \frac{5}{3} ^{ \frac{1}{3} }= \frac{3}{5} ^{- \frac{1}{3} }=> -x+2=-\frac{1}{3} => x=7/3[/tex]
[tex]d)5 \sqrt[4]{2^{x}} =160=>2 ^{\frac{x}{4} }= \frac{160}{5} =32=2^{5}=> \frac{x}{4} =5=>x=20[/tex]
[tex]b) (\frac{3}{5} )^{-x+2}= \sqrt[3]{ \frac{5}{3} } = \frac{5}{3} ^{ \frac{1}{3} }= \frac{3}{5} ^{- \frac{1}{3} }=> -x+2=-\frac{1}{3} => x=7/3[/tex]
[tex]d)5 \sqrt[4]{2^{x}} =160=>2 ^{\frac{x}{4} }= \frac{160}{5} =32=2^{5}=> \frac{x}{4} =5=>x=20[/tex]