Resposta :
40g + 72g = 112g (total de gás) CH4 = 16 g/mol 27° C + 273 K = 300 K
1 mol ---------- 16 g
x ------------- 112g x = 7 mols
PV = nRT (inicial) PV = nRT (final)
3 . V = 4,5. 0,082. 300 P . 36,9 = 7. 0,082 . 300
V = 110,7/ 3 P = 172,2 / 36,9
V = 36,9 L P = 4,67 atm
1 mol ---------- 16 g
x ------------- 112g x = 7 mols
PV = nRT (inicial) PV = nRT (final)
3 . V = 4,5. 0,082. 300 P . 36,9 = 7. 0,082 . 300
V = 110,7/ 3 P = 172,2 / 36,9
V = 36,9 L P = 4,67 atm