Resposta :
[tex]- x^{2} +5x+4=0=
\Delta= b^{2} -4.a.c=
\Delta= 5^{2}-4(-1).4=
\Delta=25+16=41
x^{1} =-+5 \sqrt{41} /2=5 \sqrt{41}
x^{2} =-+5 \sqrt{41}/2 =5 \sqrt{41} [/tex]
\Delta= b^{2} -4.a.c=
\Delta= 5^{2}-4(-1).4=
\Delta=25+16=41
x^{1} =-+5 \sqrt{41} /2=5 \sqrt{41}
x^{2} =-+5 \sqrt{41}/2 =5 \sqrt{41} [/tex]