Resposta :
a)
M=C(1+i)^n
M= 12000 (1+2/100)^2
M=12000 (1+0,020^2
M=12000.(1,02)^2
M=12000.1,0404
M= 12484,80 reais
b)
n= log M/c/log (1+i)
n= log 13000/12000/ log (1+0,02)
n=log 1,0833/ log 1,02
n= 0,03476/0,00860
n= 4,04186
n= 5 meses
M=C(1+i)^n
M= 12000 (1+2/100)^2
M=12000 (1+0,020^2
M=12000.(1,02)^2
M=12000.1,0404
M= 12484,80 reais
b)
n= log M/c/log (1+i)
n= log 13000/12000/ log (1+0,02)
n=log 1,0833/ log 1,02
n= 0,03476/0,00860
n= 4,04186
n= 5 meses