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Celio

Olá, keysse.

 

[tex]d_{AP}^2=d_{PB}^2 \Rightarrow (x-1)^2+(2x+3-2)^2=(x+2)^2+(2x+3-3)^2\\\\ \Rightarrow x^2-2x+1+4x^2+4x+1=x^2+4x+4+4x^2 \Rightarrow\\\\ \Rightarrow -2x+2=4 \Rightarrow -2x=2\Rightarrow \boxed{x=-1}\\\\[/tex]

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