Resposta :
Utiliza Baskara
onde que a = 1 b=-10 c =25
Formula = -b+ou- (b^2-4.a.c)^1/2 /2.a
Substituindo Terá :
10+ou- (100 -4 ,1 .25)^1/2 /2
10+ou- 0/2
X1= 10+0 /2 = 5
X2 = 10-0 /2 = 5
onde que a = 1 b=-10 c =25
Formula = -b+ou- (b^2-4.a.c)^1/2 /2.a
Substituindo Terá :
10+ou- (100 -4 ,1 .25)^1/2 /2
10+ou- 0/2
X1= 10+0 /2 = 5
X2 = 10-0 /2 = 5
Resposta:
[tex]S=\{5\}[/tex]
Explicação passo-a-passo:
[tex]x^{2} -10x+25=0\\\\a=1\\b=(-10)\\c=25[/tex]
[tex]\Delta=b^{2} -4ac\\\Delta=(-10)^{2}-4\times1\times25\\\Delta=100-100\\\Delta=0[/tex]
[tex]x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-10)\pm\sqrt{0} }{2\times1} \\\\x=\frac{10\pm0}{2}[/tex]
[tex]x_{1} =\frac{10+0}{2} =\frac{10}{2} =5\\\\x_{2}=\frac{10-0}{2}=\frac{10}{2} =5[/tex]