Resposta :
[tex]f(x) = x^2-4x+10=7[/tex]
[tex] x^2-4x+3=0[/tex]
[tex]x= \frac{-(-4)+- \sqrt{(-4)^2-4.1.3} }{2.1}= \frac{4+- \sqrt{4} }{2}[/tex]
[tex]= \frac{4+- 2}{2} \left \{ {{ \frac{6}{2}=3 } \atop { \frac{2}{2}=1 }} \right. [/tex]
Hugs
[tex] x^2-4x+3=0[/tex]
[tex]x= \frac{-(-4)+- \sqrt{(-4)^2-4.1.3} }{2.1}= \frac{4+- \sqrt{4} }{2}[/tex]
[tex]= \frac{4+- 2}{2} \left \{ {{ \frac{6}{2}=3 } \atop { \frac{2}{2}=1 }} \right. [/tex]
Hugs