Resposta :
Olá, Aprendiz.
[tex]A=8^{\frac13}+(\frac19)^{\frac12}+16^{\frac14}=\sqrt[3]{2^3}+\sqrt\frac1{3^2}+\sqrt[4]{2^4}=2+\frac13+2=\frac{13}3[/tex]
[tex]A=(0,25)^{0,5}+18^{0,25}+1,6^{-0,5}=(\frac14)^{\frac12}+18^{\frac14}+(\frac{16}{10})^{-\frac12}=\\ =\sqrt\frac1{2^2}+\sqrt[4]{18}+\sqrt{(\frac45)^{-1}}=\frac12+\sqrt[4]{18}+\sqrt{\frac54}=\frac12+\sqrt[4]{18}+\frac{\sqrt5}2=\\ =\sqrt[4]{18}+\frac{1+\sqrt5}2[/tex]
acredito que no segundo era 81 e não 18 !!
Vamos lá:
[tex]A = \sqrt[3]{8} +\sqrt[2]{\frac{1}{9}} + \sqrt[4]{16} \\ A = \sqrt[3]{2^{3}} +\sqrt[2]{(\frac{1}{3})^{2}} + \sqrt[4]{2^{4}} \\ A = 2 + \frac{1}{3} +2 \\ \ fazendo\ mmc = 3 \\ A = \frac{3.2}{3} +\frac{1}{3}+\frac{3.2}{3}\\ \\A = \frac{6}{3} +\frac{1}{3}+\frac{6}{3}\\ \\ A = \frac{13}{3}\\ \\ \\ \\ A = \sqrt[2]{0,25} +\sqrt[4]{81} + \sqrt[2]{1,6^{-1}} \\ \\ A = \sqrt[2]{\frac{1}{4}} +\sqrt[4]{81} + \sqrt[2]{1,6^{-1}} \\ \\ A = \sqrt[2]{\frac{1}{4}} +\sqrt[4]{81} + \sqrt[2]{\frac{16}{10}} ^{-1}} \\ \\ [/tex]
A = 1/2 + 4 +V10/4
A = 2/4+ 16/4+ V10/4
A = (18+V10)/4