Resposta :

[tex] x^{2} -4x-4=0 \\ \\ a=1 \\ b=-4 \\ c=-4 \\ \\ \Delta=b^2-4.a.c \\\ \\ \Delta=(-4)^2-4.1.(-4)=16+16=32 \\ \\ x=\frac{-b+-\sqrt{\Delta}}{2a} \\ \\ \boxed{x=\frac{4+-\sqrt{32}}{2}=\frac{4+-4\sqrt2}{2}=2+-2\sqrt2} \\ \\ \boxed{S= \{2-2\sqrt2;2+2\sqrt2 \}} [/tex]
x²-4x-4=0
a= 1 b= -4 c= -4
-b±√b²-4.a.c/2.a
-(-4)
±√(-4)² -4 . 1. (-4)/2
4±√16+16/2
x=4±√32/2
x=4±√2². 2².2/2
x=4±4√2/2
x'= 2+2√2
x''=2-2√2

Espero ter ajudado'

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