Resposta :

MATHSPHIS
[tex] \lim_{x \to 1} \frac{x^3-3x+2}{x^4-4x+3}= \\ \\ \lim_{x \to 1} \frac{3x^2-3}{4x^3-4}= \\ \\ \lim_{x \to 1} \frac{6x}{12x^2}=\frac{6.1}{12.1^2}=\frac{6}{12}=\frac{1}{2}[/tex]

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