Resposta :

ittalo25
[tex] \frac{ 2^{3x+2} }{ 8^{2x+7} } = 4^{x-1} [/tex]

[tex] \frac{ 2^{3x+2} }{ 2^{6x+21} } = 2^{2x-2} [/tex]


[tex] 2^{3x+2-6x-21} = 2^{2x-2} [/tex]

[tex]3x+2-6x-21 = 2x-2 -3x - 19 = 2x -2 -3x -19 + 2 = 2x -3x -17 = 2x -3x -2x = 17 -5x = 17 .(-1) 5x = -17 x = -17/5[/tex]
2^(3x + 2) / 2^3(2x + 7) = 2^2(x - 1)
2^(3x + 2) = 2^(6x + 21) * 2^(2x - 2)
2^(3x + 2) = 2^6x + 21 + 2x - 2
3x + 2 = 6x + 21 + 2x - 2
3x - 6x - 2x = 21 - 2 - 2
- 3x - 2x = 19 - 2
- 5x = 17 .(-1)
5x = - 17
x = - 17/5

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