Resposta :

alineramos
f(x) = x²-2x-3
x²-2x-3 = 0
delta = b² - 4ac
delta = (-2)² - 4.(1).(3)
delta = 4 - 12
delta = 8

Formula de Baskara :

x = -b +- [tex] \sqrtdelta[/tex] / 2a
x = -(-2) +- [tex] \sqrt8[/tex] / 2.(1)
x' = 2 + 4 / 2
x' = 6/2  x'= 3
x'' = 2 - 4 / 2
x'' = -2 / 2  x'' = -1

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