Resposta :

x²-5x-6=0
a= +1; b= -5; c= -6
Δ= b²-4ac
Δ= (-5)²-4.(+1).(-6)
Δ= +25+24
Δ= +49
 
x= [tex] \frac{-b+/-[tex] \sqrt{b²-4ac} [/tex]
x= [tex] \frac{-(-5)+/- \sqrt{49} }{2.1} [/tex]
x= [tex] \frac{+5+/-7}{2} [/tex]
x,=[tex] \frac{+5+7}{2} [/tex]=[tex] \frac{12}{2} [/tex]=6
x,,= [tex] \frac{+5-7}{2} [/tex]=[tex] \frac{-2}{2} [/tex]=-1
logo, x,=6 e x,,=-1

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