Resposta :
[tex]x_M=\frac{x_A+x_B}{2} \\
\\
3=\frac{-2+x}{2} \\
\\
x-2=6 \\
\\
\boxed{x=8}[/tex]
[tex]y_M=\frac{y_A+y_B}{2} \\ \\ -2=\frac{-2+y}{2} \\ \\ y-2=-4 \\ \\ \boxed{y=-2}[/tex]
Logo B(8,-2)
[tex]y_M=\frac{y_A+y_B}{2} \\ \\ -2=\frac{-2+y}{2} \\ \\ y-2=-4 \\ \\ \boxed{y=-2}[/tex]
Logo B(8,-2)