Resposta :

Sec x = 7/3
logo    1/Cosx = 7/3
Cosx = 3/7
cos²x + sen²x = 1
9/49 + sen²x = 1
sen² = 40/49
sen = - [tex]2\sqrt{10}[/tex] /49
tgx = senx/cosx
tgx = ( - [tex]2\sqrt{10}[/tex] /49)/(3/7)
tgx = - [tex]2\sqrt{10}[/tex] / 21

Cotgx = 1/tgx
cotgx = - 21 /  [tex]2\sqrt{10}[/tex]
15m/10 =  - 21 /  [tex]2\sqrt{10}[/tex]

m = [tex]\frac{-7}{\sqrt{10}}[/tex]

 

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