Resposta :
log 0,001 = log 10^-3 = -3
log(2)1/6 = log(2)1 - log(2)6 = 0 - log(2)(2x3) = log(2)2 + log(2)3 = 1 + 0,477 = 1,477
-3 + 1,477 = -1,523 (aproximadamente)
Paola
A= Log 0,001 + log 1/6 = x + (y - z + w) = - 3 + 0,585 = - 2,415
10 2
Veja desenvolvimento
Log 0,001 = x 0,001 = 10^x 10^-3 = 10^x x = - 3
10
log 1/6 = log 1 - log 6 = log 1 - log 2 + log 3 = (y - z + w) = 0 - 1 + 1,585 = 0,585
2 2 2 2 2 2
log 1 = y 1 = 2^y 2^0 = 2^y y = 0
2
log 2 = z 2 = 2^z 2^1 = 2^z z = 1
2
log 3 = w = 1,585
2