Resposta :
9 - [tex]40^{2}=(19,2)^{2}+C^{2}\\ \sqrt{1600-368,64}\approx 35,09[/tex]
10 - 4cm
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| h | |_ 13cm
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16cm
[tex]13^{2}=h^{2}+(16-4)^{2}\\ \sqrt{169-144}\\ \sqrt{25}=5\\[/tex]
Então o perimetro vale: 13+4+5+16=38