Resposta :

podemos tirar o mmc

 

 t+5/8 - t-2/2 = 1/3

 

(t+5-4t+8)/8=1/3

 

-3t+13=8/3

-3t=8/3-13

-3t=-31/3

t=31/9

[tex]\frac{t+5}{8} - \frac{t-2}{2} = \frac{1}{3}[/tex]

 

[tex]\frac{t+5_{x3}}{8_{x3}} - \frac{t-2_{x4}}{2_{x4}} = \frac{1_{x8}}{3_{x8}}[/tex]

 

[tex]\frac{3(t+5)}{24} - \frac{12(t-2)}{24} = \frac{8}{24}[/tex]

 

[tex]\frac{3t+15}{24} - \frac{12t-24}{24} = \frac{8}{24} \\\\ anula \ os \ denominadores[/tex]

 

[tex]3t+15- 12t-24= 8[/tex]

 

[tex]3t- 12t= 8 - 15 + 24[/tex]

 

[tex]-9t= 31[/tex]

 

[tex]-t = \frac{31}{9} \cdot (-1)[/tex]

 

[tex]\boxed{t = -\frac{31}{9}}[/tex]

Outras perguntas