Resposta :

x²+4x-12 = 0

Δ = b²-4ac

Δ = 4²-4.1.(-12)

Δ = 16+48

Δ = 64

 

x = (-b+/-\/Δ)/2a

x = (-4+/-\/64)/2

x = (-4+/-8)/2

x' = (-4+8)/2 = 4/2 = 2

x" = (-4-8)/2 = -12/2 = -6

 

S: {2;-6}

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