Resposta :
f(x) = x²-x+1
a)
f(0) =0²-0+1
f(0) = 1
b)
f(x) = -2
-2 = x²-x+1
x² - x +3 = 0
(-b ±√(b²-4ac))/2
(1 ±√(1-4.3))/2
(1 ±√-11)/2
x = 1/2
c)
2²-2+1+(-2)²-(-2)+1
4-2+1+4+2+1
3+7
10
d) ???
Seja f: R -> Ruma função definida pela lei f(x)=x²-x+1. Determine:
a) f(0)
b)-2
c) f(2)+f(-2)
d)f (\sqrt{2}
f(x) = x²-x+1
a)
f(0) =0²-0+1
f(0) = 1
b)
f(x) = -2
-2 = x²-x+1
x² - x +3 = 0
(-b ±√(b²-4ac))/2
(1 ±√(1-4.3))/2
(1 ±√-11)/2
x = 1/2
c)
2²-2+1+(-2)²-(-2)+1
4-2+1+4+2+1
3+7
10
d) ???