Resposta :

[tex]1/2.\frac{1}{\sqrt{x^{2}-4}}.2x\\ \frac{x}{\sqrt{x^{2}-4}}[/tex]

ManoelPedro

[tex]\sqrt{x^{2}-4}[/tex]

 

fazendo u=x²-4 temos:

               v= x²

a primeira derivada da seguinte maneira:   √u=[tex]u^{\frac{1}{2}}[/tex]

                                                                                   =½*[tex]u^{\frac{1}{2}-1}[/tex]*v²

                                                                                   =½[tex] *u^{\frac{-1}{2}}[/tex]*2v

                                                                                   =½*√[tex]u^{-1}[/tex]*2x

                                                                                   =[tex]\frac{x}{x^{2}-4}[/tex]

Espero ter ajudado

 

thiau

 

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