Resposta :
[tex]M=C.(1+i)^{t}\\ M=C+J=10000+1088,53=11088,53\\ \\ 11088,53=10000(1+0,013)^{t}\\ \\ 1,108853=1,013^{t}\\ \\ ln(1,108853)=t.ln(1,013)\\ \\ t=ln(1,108853)/(ln1,013)\\ \\ t=7,9999 \ \ aproximadamente 8 [/tex]
[tex]M=C.(1+i)^{t}\\ M=C+J=10000+1088,53=11088,53\\ \\ 11088,53=10000(1+0,013)^{t}\\ \\ 1,108853=1,013^{t}\\ \\ ln(1,108853)=t.ln(1,013)\\ \\ t=ln(1,108853)/(ln1,013)\\ \\ t=7,9999 \ \ aproximadamente 8 [/tex]