Sendo f(x)= -x³+5x-1, calcule f(0) - f(-1) + 3f(2)
Sendo f(x)= -3x²+5x, calcule f(0) - f(-1) + f(2)
b. -3x² +5x
F=0
-3. 0² + 5.0
-3.0+0= 0
f=-1
-3.(-1)²+5.(-1)
-3.1-5
-3-5=-8
F=2
-3.2²+5.2
-3.4+10
-12+10=-2
f(x) = -x³+5x-1
f(0) = 0 + 0 - 1
f(0) = -1
f(-1) = -(-1)³ + 5.(-1) - 1 = -(-1) - 5 - 1 = 1 - 5 - 1 = - 5
3f(2) = 3.(-2³+5.2-1) = 3.(-8+10-1) = 3.1 = 3
f(0) - f(-1) + 3f(2) = -1 - (-5) + 3 = -1+5+3 = 7
