Resposta :
Observe que:
[tex]16^{-1}=\dfrac{1}{16}[/tex]
[tex]2^{-5}=\left(\dfrac{1}{2}\right)^5=\dfrac{1}{32}[/tex]
[tex]5^{-1}=\dfrac{1}{5}[/tex]
Logo, podemos afirmar que:
[tex]\text{X}=16^{-1}\div2^{-5}\cdot5^{-1}=\dfrac{1}{16}\div\dfrac{1}{32}\cdot\dfrac{1}{5}[/tex]
[tex]\text{X}=\dfrac{32}{16}\cdot\dfrac{1}{5}[/tex]
[tex]\text{X}=2\cdot\dfrac{1}{5}[/tex]
[tex]\text{X}=\dfrac{2}{5}[/tex]