Olá, Jacque.
[tex]A=\left[\begin{array}{cc}1 & 3 \\ 2 & 4 \end{array}\right], B+\left[\begin{array}{cc}-1 & 2 \\ 3 & 1 \end{array}\right]\\\\\\ A+B=\left[\begin{array}{cc}1 -1& 3 +2 \\ 2+3 & 4+1 \end{array}\right]=\left[\begin{array}{cc}0& 5 \\ 5& 5 \end{array}\right]\\\\\\ (A+B)^t=\left[\begin{array}{cc}0& 5 \\ 5& 5 \end{array}\right]\\\\\\ det(A + B ) ^t=0\cdot5-5\cdot5=\boxed{-25}[/tex]
