Resposta :

Celio
Olá, Francisca.

Temos que:

[tex]\text{A}=8^{\frac{1}{3}}+16^{\frac{1}{4}}-(-2)^2+8^{\frac{4}{3}}[/tex]

Observe que:

[tex]8^{\frac{1}{3}}=\sqrt[3]{8^1}=2\\\\16^{\frac{1}{4}}=\sqrt[4]{16}=2\\\\(-2)^2=(-2)\times(-2)=2^2=4\\\\8^{\frac{4}{3}}=\sqrt[3]{8^4}=\sqrt[3]{8^3\cdot8}=8\sqrt[3]{8}=8\times2=16[/tex]

Logo:

[tex]\text{A}=2+2-4+16=16[/tex]

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