Resposta :
Olá, Gabreu.
[tex]\frac{(-3)^{40} +3.(-3)^{39}-(-3)^{2}-3^{2}+3}{[(-2^{3})^{2}-(-7)^{2}].0,02}=\\\\ =\frac{\overbrace{(-3).(-3)^{39} +3.(-3)^{39}}^{=0}-9-9+3}{[(-8)^{2}-49].\frac2{100}}=\\\\ =\frac{-15}{[64-49].\frac1{50}}=\\\\ =-\frac{15}{15}\cdot 50=\\\\ =\boxed{-50} [/tex]
Resposta: letra "b"