Resposta :
[tex]0,333... + \frac{1}{2} - \frac{\frac{2}{3}}{2} = \\\\ \frac{3}{9} + \frac{1}{2} - \frac{2}{3} \div 2 = \\\\ \frac{3^{\div 3}}{9^{\div 3}} + \frac{1}{2} - \frac{2}{3} \times \frac{1}{2} = \\\\ \frac{1}{3} + \frac{1}{2} - \frac{1}{3} = \\\\ \frac{1}{2} + 0 = \\\\ \boxed{\frac{1}{2}}[/tex]
[tex]0,333...+1/2-(2/3:2)=\frac{3}{9}+\frac{1}{2}-(\frac{\frac{2}{3}}{2})=\frac{1}{3}+\frac{1}{2}-\frac{1}{3}=\frac{1}{2}[/tex]