Resposta :
1a) C(10) = 100 +2(10) = 100 + 20 = 120
b) C(20) = 100 +2(20) = 100 + 40 = 140
2a) C(10) = 3(10)³ - 24(10)² + 600(10) + 400. = 3000-2400 + 6000+400 = 7000
b) C(20) = 3(20)³ - 24(20)² + 600(20) + 400
= 24000-9600+12000+400
= 26800