Resposta :
Resposta:
2x² - 11x + 5 = 0
coeficientes
a = 2
b = -11
c = 5
Δ = b² -4ac
Δ = (-11)² - 4(2)(5)
Δ = 121 - 40
Δ = 81
[tex]x=\dfrac{-b\pm\sqrt{\Delta} }{2a}\\ \\ \\x= \dfrac{-(-11)\pm\sqrt{81} }{2.(2)}=\dfrac{11\pm9}{4}\\ \\ \\ x'=\dfrac{11+9}{4}=\dfrac{20}{4}=\boxed{5}\\ \\ \\ x"=\dfrac{11-9}{4}=\dfrac{2}{4}=\boxed{\dfrac{1}{2}}[/tex]