Respondido

If zeroes of the polynomial p(x) = kx2 – 29x + 10 are reciprocal of each other, then find the
value of k.

Resposta :

Teus90

Resposta:

Let the zeroes of the polynomial be a and 1/a, where a is a constant.

According to the given condition, the product of the zeroes is equal to 1:

a * 1/a = 1

This implies that a^2 = 1

Therefore, a = 1 or a = -1

If a = 1, then the zeroes are 1 and 1/1 = 1, which are not reciprocal of each other.

If a = -1, then the zeroes are -1 and 1/(-1) = -1, which are reciprocal of each other.

Therefore, the value of k is the product of the zeroes:

k = (-1)(-1) = 1

Thus, the value of k is 1.

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